B.Sc. II Practical -III Expt.- 07 Title: INDEX NUMBER-I (Computations of Index Numbers by different methods)

 

P. V. P. Mahavidyalaya, Kavathe Mahankal

  DEPARTMENT OF STATISTICS

Expt.- 07                                   B. Sc. II / Practical-III                       Date: 17/08/2023 

 Title: INDEX NUMBER-I (Computations of Index Numbers by different methods)

 

 Q. 1. Obtain price index number by average of price relative’s method using average as:

(i)   Arithmetic mean and (ii) Geometric mean. 

Commodity

A

B

C

D

Price in Rs ( Base Year)

100

80

40

10

Price in Rs. ( Current Year)

150

100

50

20

 

Q. 2. Compute price index number for the following data by applying weighted average of price relatives by using average as:

(i) Arithmetic mean  and (ii) Geometric mean. 

Commodity

Price in 2015(Rs.)

Price in 2020 (Rs.)

Weight

Wheat

22.00

32.50

35

Sugar

23.00

33.25

20

Milk

21.50

31.75

15

Q. 3. Consider the following prices and quantities of four commodities A, B, C and D for base and current year:

 

Commodity

Base Year

Current Year

Price

Quantity

Price

Quantity

A

8

50

10

60

B

10

40

12

50

C

5

100

8

120

D

6

300

9

250

 

    Compute:  i) Laspeyre’s, Paasche’s and   Fisher’s price and quantity index number.

ii) Value index number. Comment on values of each of the above indices.

 Q.4. Construct the price Index Number by simple aggregate method.

Items

A

B

C

D

Price  in 1965 ( Po)

50

100

30

40

Price  in 1971 ( P1)

65

105

50

40

 

 

  ***



Aim: – Computation and interpretation of values of various index numbers. Testing various tests of Index Numbers.

 Statistical Tools: Simple and weighted index numbers. Various Tests of Index Numbers.

 Required Formulae:–

Results:-

Price index number for given data by average of price relatives method by using average as:

(i)   Arithmetic mean is equal to 150 and (ii) Geometric mean is equal to 147.14

 Price index number for given data by weighted average of price relatives method

(i)   By using average as Arithmetic mean is equal to 146.81

(ii)   By using average as Geometric mean is equal to 146.80

Results:- For given data set:

i)   Laspeyre’s price and quantity index numbers are respectively, 144.5161 and 99.3548.

 Therefore, we conclude that prices of commodities are increased by around 45% but quantities (consumption) of commodities are decreased by around 1% in current year than that of base year.

 ii)   Paasche’s price and quantity index numbers are respectively, 143.1818 and 98.4375.

 Therefore, we conclude that prices of commodities are increased by around 43% but quantities (consumption) of commodities are decreased by around 2% in current year than that of base year.

iii)   Fisher’s price and quantity index numbers are respectively, 143.8474 and 98.8951.

Therefore, we conclude that prices of commodities are increased by around 44% but quantities (consumption) of commodities are decreased by around 1% in current year than that of base year.

 iv)  Value index number is equal to 142.2581.

 Therefore, we conclude that value of commodities is increased by around 42% in current year than that of base year.

 ***

P. V. P. Mahavidyalaya, Kavathe Mahankal

DEPARTMENT OF STATISTICS

 Expt.- 08                                   B. Sc. II / Practical-III                       Date: 24 /08 /2023 

 Title: INDEX NUMBER-II (Cost of living index number and tests of index numbers)

 

Q. 1. Consider the Data given in above problem Q.3 and discuss about time reversal test for price indices and factor reversal test for each of the followings:

       i) Laspeyre’s index number ii) Paasche’s index number   iii) Fisher’s index number

 Q.2. Following are the wage index numbers (I.N.) of industrial workers in two                              companies. Compare the two series and comment.

Year

1990

1991

1992

1993

1994

1995

I.N. of Company A with base year 1992

60

90

100

140

160

200

I.N. of Company B with base year 1985

210

230

250

300

250

400

       

 Q.3. Calculate a cost of living index number for the following two data sets by using       appropriate formula and comment on them:

                                                            


Q:-4 The following data relate to the income of the people & the general price index numbers of prices of a certain region. Calculate i) Real Income ii) Index number of Real Income with 1968 as the base.       

Year

1968

1969

1970

1971

1972

1973

1974

Income in Rs.

800

819

825

876

920

938

924

G. P. Index No.

100

105

110

120

125

140

140

                                                          ***

 Solution to Problem No. 1:

Results:-

 i)  By definition of Time Reversal Test and by above computations we conclude that only Fisher’s Price indices satisfies time reversal test.

 ii)   By definition of Factor Test and by above computations we conclude that only Fisher’s Index Number satisfies Factor test.

 Solution to Problem No. 2:

Here first we will obtain indices for both companies A and B with common base year 1992: 

Year

1990

1991

1992

1993

1994

1995

I.N. of Company A with base year 1992

60

90

100

140

160

200

I.N. of Company B with base year 1985

210

230

250

300

250

400

I.N. of Company B with base year 1992

84

92

100

120

100

160

 

Results:-

 Observing wage indices for both companies with common base year 1992 from above table , we conclude that wages of employees in company B are more than that of A up to year 1991, but from the year 1993 wages of employees in company A are more than that of B.

Solution to Problem No. 3:

 Data Set I

Commodity

Base Year

Current Year

 

 

(p0)

(q0)

(p1)

(q1)

q0 p0

q0p1 

     A

5

50

7

50

250

350

B

12

10

15

100

120

150

C

8

30

10

30

240

300

D

4

40

8

4

160

320

E

9

  10

12

   10

90

120

 

 

 

 

 

860

1240

Therefore, Cost of living index no. = 1240/860 = 144.186

Data Set II

Items

Group Index Number (I)

Weight (w)

wI

Food

350

50

17500

Fuel and Lighting

200

10

2000

Clothing

240

10

2400

House Rent

160

10

1600

Miscellaneous

250

20

5000

 

Total:-

100

28500


Therefore, Cost of living index no. = 28500/100 = 285

Results:

i)   Cost of Living Index Number or Consumer Price Index Number (CPI) for Data Set I is equal to 144.186.This number is greater than 100 by 44, therefore we conclude that cost in current year is increased and to maintain same living standard as that of base year in current year, it requires to spend 44% more money in current year with respect to base year. It indicates that purchasing power of money is decreased by 44% in current with respect to base year.

 ii)   Cost of Living Index Number or Consumer Price Index Number (CPI) for Data Set II is equal to 285.This number is greater than 100 by 185, therefore we conclude that cost in current year is increased and to maintain same living standard as that of base year in current year, it requires to spend 185% more money in current year with respect to base year. It indicates that purchasing power of money is decreased by 185% in current with respect to base year.

Solution to Problem No. 4:

                                                                          ***

P.V.P. MAHAVIDYALAYA, KAVATHE MAHANKAL

DEPARTMENT OF STATISTICS

Expt. No.:1                            B. Sc. II / Practical-III                                      Date:

Title: Multiple Regressions

 Q1. Consider the following variance co-variance matrix between X1, X2 and X3:

1177

1035

444

𝑆 = [1035

4537

1501]

444

1501

787

If 𝑋¯1 = 150.0909, 𝑋¯2= 62.4546 and 𝑋¯3= 195.0 then obtain multiple regression equation of X1 on X2 and X3.

 Q2. Consider the following co-relation matrix (R) between X1, X2 and X3: 

 

1

0.4479

0.4611

𝑅 =

[0.4479

1

0.7944]

 

0.4611

0.7944

1

If 𝑋¯1 = 150.0909, 𝑋¯2= 62.4546, 𝑋¯3= 195.0, σ1 = 34.3074, σ2 = 67.3573   and σ3 = 28.0535

then obtain multiple regression equation of X2 on X1 and X3.

 Q3. Consider the data on systolic blood pressure (X1), age in years (X2) and weight in pound (X3):

Observation No.

1

2

3

4

5

6

7

8

9

10

11

X1

132

143

153

162

154

168

137

159

128

166

149

X2

52

59

67

73

64

74

54

65

46

72

61

X3

173

184

194

211

196

220

188

207

167

217

188

 Fit the linear regression equation of systolic blood pressure on age and weight. Hence estimate systolic blood pressure when age and weight of a patient are 60 years and 200 pounds, respectively.

 Q4. Following is the data on phosphate adsorption index ( Y ), amount of extractable iron (X1) and amount of extractable aluminum (X2): 

Observation No.

1

2

3

4

5

6

7

8

9

10

11

12

13

Y

4

18

14

18

26

26

21

30

28

36

65

62

40

X1

61

175

111

124

130

178

169

169

160

244

257

333

199

X2

13

21

24

23

64

38

33

61

39

71

112

88

54

 

(a)   Fit the linear regression equation of phosphate adsorption index on amount of extractable iron and amount of extractable aluminum. Hence estimate phosphate adsorption index when amount of extractable iron and amount of extractable aluminum are 250 pounds and 100 pounds, respectively.

(b)  Obtain residual of Y due to X1 and X2 for each observation and show that its sum is zero.

 (c)  Draw residual plot and comment on it.

***

Procedure of Writing Answer to Practical 

 Aim : Obtaining linear multiple regression equations between three variables and estimating value of dependent variable when values of independent variables are given. 

Statistical Tools : Linear multiple regression equations by least square method. Required Formulae : Let (X1k, X2k, X3k), k = 1, 2, ..., N be N observations on quantitative variables (X1, X, X). 

 The linear regression equation ( plane ) of X1 on X and X by least square method is given by : 




***













DEPARTMENT OF STATISTICS

 Expt.- 10                                   B. Sc. II / Practical-III                       Date: 27 /10 /2023 

 Title: National Income

Q 1 : From the following data  determine GDP at factor cost.
          a)  
GNP at factor cost=15000 crores b) income at factor cost from foreign nationals,                      residing in the country=5000 crores c)income(net) from abroad=1000 crores.

   Q 2  : Given that GNP at market price is 50000 crores the total of subsidies is 5000 crores and                          indirect taxes paid total up to 7000 crores compute GNP at factor cost.

   Q 3 : If GDP is 90000/- crores and depreciation is 2% of GDP find Net Domestic Product (NDP).

  Q 4. Compute NNP at factor cost given that NDP at factor cost= 24000Crores, imports= 6000                            crores and Exports= 4000 crores.

 Q 5 : Determine NNP at factor cost given the following GNP at market price = 100000/- crores,                      Indirect taxes =7000 Crores, Subsidies =200 crores and depreciation=9000 crores.  Further                     find NDP if net income from abroad is 2000 Crores.

 Q 6 : Compute GNP, NNP and NDP given GDP= 24000 crores, net income from abroad= 3000 crores,              net Exports= 1000 crores, depreciation= 500 crores.

 Q 7 : From data given below find GNP at factor cost, NNP at Factor cost, NDP at factor cost, NDP at               market price GNP at market price= 97000 crores, net factor income from abroad=- 200 crores,               capital consumption allowance(depreciation)= 6000 crores, net indirect taxes= 10000 crores.

***

 Procedure of Writing Answer to Practical

 Aim: – Computation of various terms related to National Income. 

Statistical Tools: – Various formulae related to National Income.

Required Formulae:–

Let GDP = Gross National Product; GNP = Gross National Product; NDP = Net Domestic Product; NNP = Net National Product;

 

1.      GNP (Factor Cost) = GDP (Factor Cost) + Net Factor Income from Abroad Income at factor cost from foreign Nationals

2.      GNP (Factor cost) = GNP (Market price) + Subsidies – Taxes

3.      NDP = GDP Depreciation

4.      NNP (Factor Cost) = NDP (Factor Cost) + X – M    ,

where X = Exports           and M = Imports.

5.      NNP( Factor cost) = GNP( Factor cost) Depreciation

6.      GNP( Factor cost) = GNP( Market price) + Subsidies Indirect Taxes

7.      NDP = NNP Net Income from Abroad

8.      GNP = GDP + Net Income from Abroad + Exports

9.      NNP = GDP + Net Income from Abroad + Exports Depreciation

10.  NNP (Factor cost) = GNP (Market price) – Taxes Depreciation

11.  NDP (Factor cost) = NNP (Factor cost) + Import Export Net Income from Abroad

12.  NNP (Market Price) = NNP (Factor Cost) + Net Indirect tax

 

Data Source: – Provided in Practical Sheet for every problem.

Computations and Results:

 Solution to Problem No. P1:

We know,

GNP (Factor Cost) = GDP (Factor Cost) + Net Factor Income from Abroad Income at Factor Cost from Foreign Nationals

 

Substituting given values in above formula: 15000 = GDP (Factor Cost) + 1000 5000

 

GDP (Factor Cost) = 15000 + 4000 = 19000

 Result:-

GDP at Factor Cost = 19000


 

Solution to Problem No. P2:

We know,

GNP (Factor cost) = GNP (Market price) + Subsidies – Taxes Substituting given values in above formula:

GNP (Factor cost) = 50000 + 5000 – 7000

GNP (Factor cost) = 48000

 

Result:-

GNP at factor cost is equal to 48000 crores.

 

Solution to Problem No. P3:

We know,

NDP = GDP Depreciation

Given: GDP = 90000 and depreciation is 2% of GDP = 90000 × 2 = 1800

100

⸫ NDP = 90000 – 1800 = 88200

 

Results:-

Net Domestic Product is equal to 88200 crores

 

Solution to Problem No. P4:

We know,

NNP (Factor Cost) = NDP (Factor Cost) + X – M    , where X = Exports    and M = Imports.

 

Given: NNP = NDP (Factor Cost) = 24000 Crore, X = 4000 Crore and M = 6000 Crore.

⸫ NNP (Factor Cost) = 24000 + 4000 – 6000 = 22000

 

Results:-

NNP at factor cost is equal to 22000 Crore

 

Solution to Problem No. P5:

We know,

NNP( Factor cost) = GNP( Factor cost) Depreciation

 

GNP( Factor cost) = GNP( Market price) + Subsidies – Indirect Taxes and

NDP = NNP – Net Income from Abroad Given:

GNP ( Market price ) = 100000/- crores, Indirect Taxes = 7000 Crores, Subsidies = 200 crores and Depreciation = 9000 crores and

Net Income from Abroad = 2000 Crores.

⸫ GNP( Factor cost) = 100000 + 200 – 7000 = 93200

NNP( Factor cost) = GNP( Factor cost) Depreciation

= 93200 – 9000 = 84200


 

NDP = 84200 – 2000 = 80200

Results:-

i) NNP at factor cost is equal to 84200/- Crores ii) NDP is equal to 80200/- Crores

 

Solution to Problem No. P6:

We know,

GNP = GDP + Net Income from Abroad + Exports

NNP = GDP + Net Income from Abroad + Exports – Depreciation

NDP = GDP – Depreciation

Given:

GDP= 24000 crores, Net Income from Abroad = 3000 crores, Net Exports = 1000 crores and Depreciation = 500 crores.

Substituting given values in above formulae:

GNP = 24000 + 3000 + 1000 = 28000

NNP = 24000 + 3000 + 1000 – 500 = 27500

NDP = 24000 – 500 = 23500

 

Results:-

i)  GNP is equal to 28000/- Crores

ii)   NNP is equal to 27500/- Crores

iii)   NDP is equal to 23500/- Crores

 

Solution to Problem No. P7:

We know,

GNP (Factor cost) = GNP (market price) + Subsidies – Taxes NNP (Factor cost) = GNP (market price) Taxes – Depreciation

NDP (Factor cost) = NNP (Factor cost) + Import – Export – Net Income from Abroad NNP (Market Price) = NNP (Factor Cost) + Net Indirect tax

 

Given:

GNP at market price = 97000 crores, Net factor Income from Abroad =- 200 crores, Capital consumption allowance (Depreciation) = 6000 crores and

Net Indirect Taxes = 10000 crores.

GNP (Factor cost) = 97000 + 0 – 10000 = 87000 (assuming no subsidy) NNP (Factor cost) = 97000 – 10000 – 6000 = 81000

NDP (Factor cost) = 81000 + Import – Export – (–200)

= 81000 + 200 = 81200 (assuming Import = Export) NNP (Market Price) = NNP (Factor Cost) + Net Indirect tax

= 81000 + 10000 = 91000

Results:-

i) GNP (Factor cost) = 87000/- Crores .         ii) NNP (Factor cost) = 81000/- Crores .

iii) NDP (Factor cost) = 81200 /- Crores .      iv) NNP (Market Price) = 91000/- Crores .

***





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